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In lua's case, the language is intended to be an embedded scripting language, so any changes that make the language more complex or potentially make the compiler/runtime even slightly larger or slower may go against this objective This is my command script If you implement each and every tiny feature, you can end up with a 'kitchen sink' language
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Any idea why this is wrong in lua Now i want to kill the player with the name paul If pieza == 1 then if rotacion == 1 then piezas = cuadrado1 else if rotacion == 2 then piezas =
Because control structures in lua only consider nil and false to be false, and anything else to be true, this will always enter the if statement, which is not what you want either
There is no way that you can use binary operators like those provided in programming languages to compare a single variable to a list of values. In lua asked 14 years, 8 months ago modified 1 year, 2 months ago viewed 80k times How to check if a table contains an element in lua Asked 15 years, 8 months ago modified 4 years, 7 months ago viewed 323k times
I'm new to lua, and need to know how to install it on windows I've tried and am unable to run the sample When i try to compile it 100% success is shown, but when i click the run button it shows t. 45 if you are splitting a string in lua, you should try the string.gmatch () or string.sub () methods
Use the string.sub () method if you know the index you wish to split the string at, or use the string.gmatch () if you will parse the string to find the location to split the string at
Example using string.gmatch () from lua 5.1 reference manual: Is there a common way to get the current time in or with milliseconds There is os.time(), but it only provides full seconds. I want to make a command that would kill a player you specify
Let's say i type "kill/paul"
